16.設(shè),若當(dāng)時(shí).取得極大值.時(shí).取得極小值.則的取值范圍是 . 解答應(yīng)寫(xiě)出文字說(shuō)明.證明過(guò)程或推演步驟. 查看更多

 

題目列表(包括答案和解析)

設(shè),若當(dāng)時(shí),取得極大值,時(shí),取得極小值,則的取值范圍是         .

查看答案和解析>>

21.設(shè)函數(shù)

(I)若當(dāng)時(shí),取得極值,求的值,并討論的單調(diào)性;

(II)若存在極值,求的取值范圍,并證明所有極值之和大于.

查看答案和解析>>

設(shè)函數(shù)

(I)若當(dāng)時(shí),取得極值,求的值,并討論的單調(diào)性;

(II)若存在極值,求的取值范圍,并證明所有極值之和大于

查看答案和解析>>

(12分)設(shè)函數(shù)

(1)若當(dāng)時(shí),取得極值,求值,并討論的單調(diào)性.

(2)若存在極值,求的取值范圍,并證明所有極值之和大于

 

查看答案和解析>>

(12分)設(shè)函數(shù)
(1)若當(dāng)時(shí),取得極值,求值,并討論的單調(diào)性.
(2)若存在極值,求的取值范圍,并證明所有極值之和大于

查看答案和解析>>

一.選擇題

1―5  CBABA   6―10  CADDA

二.填空題

11.       12.()       13.2          14.         15.

16.(1,4)

三.解答題

數(shù)學(xué)理數(shù)學(xué)理17,解:①         =2(1,0)                      (2分)             

        ?,                                        (4分)

?

        cos              =

 

        由,  ,    即B=              (6分)

                                               (7分)

                                                        (9分)

                                                        (11分)

的取值范圍是(,1                                                      (13分)

18.解:①設(shè)雙曲線方程為:  ()                                 (1分)

由橢圓,求得兩焦點(diǎn),                                           (3分)

,又為一條漸近線

, 解得:                                                     (5分)

                                                    (6分)

②設(shè),則                                                      (7分)

      

?                             (9分)

,  ?              (10分)

                                                (11分)

  ?

?                                        (13分)

<style id="bukho"></style>

<strong id="bukho"><font id="bukho"><del id="bukho"></del></font></strong>
        1.   單減區(qū)間為[]        (6分)

           

          ②(i)當(dāng)                                                      (8分)

          (ii)當(dāng),

          ,  (),,

          則有                                                                     (10分)

                                                         (11分)

            在(0,1]上單調(diào)遞減                     (12分)

                                                           (13分)

          20.解:①       

                                                                  (2分)

          從而數(shù)列{}是首項(xiàng)為1,公差為C的等差數(shù)列

            即                                (4分)

           

             即………………※              (6分)

          當(dāng)n=1時(shí),由※得:c<0                                                    (7分)

          當(dāng)n=2時(shí),由※得:                                                 (8分)

          當(dāng)n=3時(shí),由※得:                                                 (9分)

          當(dāng)

              (

                                                    (11分)

                                   (12分)

          綜上分析可知,滿(mǎn)足條件的實(shí)數(shù)c不存在.                                    (13分)

          21.解:①設(shè)過(guò)A作拋物線的切線斜率為K,則切線方程:

                                                                          (2分)

              即

                                                                                                             (3分)

          ②設(shè)   又

               

                                                                   (4分)

          同理可得 

                                                          (5分)

          又兩切點(diǎn)交于  ,

                                         (6分)

          ③由  可得:

           

                                                          (8分)

                            (9分)

           

          當(dāng) 

          當(dāng) 

                                                               (11分)

          當(dāng)且僅當(dāng),取 “=”,此時(shí)

                                                 (12分)

          22.①證明:由,    

            即證

            ()                                    (1分)

          當(dāng)  

                即:                          (3分)

            ()    

          當(dāng)   

             

                                                                   (6分)

          ②由      

          數(shù)列

                                                        (8分)

          由①可知, 

                              (10分)

          由錯(cuò)位相減法得:                                       (11分)

                                              (12分)

           

           


          同步練習(xí)冊(cè)答案