解:(1))(9.6-10
÷1.25)÷(1
×75%),
=(9.6-8.4)÷1,
=1.2÷1,
=1.2;
(2)
×39+
×25+
×
,
=
×13+
×25+
,
=(13+25+
)×
,
=40×
,
=30;
(3)
÷[32×(1-
)+
]
=
÷[32×
+
]
=
÷[12+
]
=
×
,
=
;
(4))[1
+2
÷(3
-1.125)]×
-
=[1
+
×
]×
-
,
=[1
+
]×
-
=
,
=
,
=
(5)0.125×
+
×8.25+12.5%+0.374×48+0.62×37.4-3.74,
=
×
+
×8.25+
+3.74×4.8+6.2×3.74-3.74,
=
×(0.75+8.25+1)+3.74×(4.8+6.2-1),
=
×10+3.74×10,
=1.25+37.4,
=38.65.
分析:(1)先算兩個(gè)小括號(hào)里面的除法和乘法,再算第一個(gè)小括號(hào)里面的減法,最后算括號(hào)外的除法;
(2)根據(jù)乘法分配律進(jìn)行計(jì)算,
(3)先算小括號(hào)里面的減法,再算中括號(hào)里面的乘法,然后算中括號(hào)里面的加法,最后算括號(hào)外的除法;
(4)先先算小括號(hào)里面的減法,再算中括號(hào)里面除法,接著算中括號(hào)里面的加法,然后算括號(hào)外的乘法,最后算括號(hào)外的減法;
(5)根據(jù)乘法分配律進(jìn)行計(jì)算.
點(diǎn)評(píng):本題綜合考查了學(xué)生的計(jì)算能力,以及在計(jì)算中靈活運(yùn)用簡(jiǎn)便算法的能力.