解:(1)4000-3456÷32×5,
=4000-108×5,
=4000-540,
=3460;
(2)3.68-3.6×0.2+0.18,
=3.68+0.18-0.72,
=3.86-0.72,
=3.14;
(3)48×9.9+48×0.1,
=48×(9.9+0.1),
=48×10,
=48;
(4)(1-
)÷0.25×4,
=
÷
×4,
=1×4,
=4;
(5)(6-6×
)÷12,
=(6-4)÷12,
=2÷12,
=
;
(6)2÷[
+(
)],
=2÷[
+(
-
)],
=2÷[
+
],
=2÷1,
=2.
分析:(1)按運算順序計算,先算除法和乘法,再算減法;
(2)可以用加法交換律,把原式變?yōu)?.68+0.18-0.72,這樣在相減時,就不用退位了;
(3)用乘法分配律的逆運算簡算;
(4)把小數(shù)化成分?jǐn)?shù),從左向右依次計算;
(5)先算括號內(nèi)的,再算括號外的,得數(shù)不是整數(shù)或純小數(shù)的,要化成分?jǐn)?shù);
(6)按運算順序計算,先算小括號內(nèi)的,再算中括號內(nèi)的,最后算括號外的.
點評:對于計算性題目,應(yīng)注意審題,看能否用簡便算法,能簡算的就要堅持用簡算的方法,不能簡算的按運算順序進行計算.