解:(1)490+6510÷(101-98)×217,
=490+6510÷3×217,
=490+2170×217,
=490+470890,
=471380;
(2)3
×(7
-1
)×0.3÷1
,
=3
×
×0.3÷1
,
=
×
×
×
,
=(
×
)×(
×
),
=1×
,
=
;
(3)41.2×8.1-11×9
+53.7×1.9,
=333.72-101.75+102.03,
=231.97+102.03,
=334;
(4)(2890+
+
+
)÷(
+
+
),
=2890÷(
+
+
)+(
+
+
)÷(
+
+
),
=2890÷(
+
+
)+1,
=(2890×120)÷[120×(
+
+
)]+1,
=(2890×120)÷[120×
+120×
+120×
]+1,
=(2890×120)÷[100+105+84]+1,
=2890×120÷289+1,
=2890÷289×120+1,
=10×120+1,
=1200,
=1201;
(5)
+
+
+…+
+1+2+4+8+…+512,
=(
+
+
+…+
+
-
)+(1+2+4+8+…+512+1-1);
=(1-
)+(512×2-1),
=
+1023,
=1023
.
分析:(1)先算小括號里面的減法,再算括號外的除法,然后算乘法,最后算加法;
(2)先算小括號里面的減法,再根據(jù)乘法結(jié)合律簡算;
(3)先同時(shí)運(yùn)算乘法,然后再算減法,最后算加法.
(4)先把(2890+
+
+
)÷(
+
+
)分成2890÷(
+
+
)+(
+
+
)÷(
+
+
),然后在根據(jù)商不變規(guī)律簡算.
(5)前面每個(gè)分母都是后面的兩倍,如果加多一個(gè)
,分?jǐn)?shù)部分就等于1.
+
+
+…+
=1-
;
如果1+2+4+8+…+512加多一個(gè)1,后面整數(shù)部分就等于2×512,1+2+4+8+…+512=2×512-1=1023;再把這兩部分加在一起即可;
點(diǎn)評:本題考查了較復(fù)雜的簡便運(yùn)算,注意找清楚規(guī)律,再根據(jù)規(guī)律化簡.