已知定義域在R上的單調(diào)函數(shù),存在實(shí)數(shù).使得對(duì)于任意的實(shí)數(shù).總有恒成立. 查看更多

 

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已知定義域在R上的單調(diào)函數(shù)y=f(x),存在實(shí)數(shù)x0,使得對(duì)于任意的實(shí)數(shù)x1,x2,總有f(x0x1+x0x2)=f(x0)+f(x1)+f(x2)恒成立.
(1)求x0的值;
(2)若f(x0)=1,且對(duì)任意正整數(shù)n,有an=
1
f(n)
,bn=f(
1
2n
)+1,記Tn=b1b2+b2b3+…+bnbn+1,求an與Tn;
(3)在(2)的條件下,若不等式an+1+an+2+…+a2n
4
35
[log
1
2
(x+1)-log
1
2
(9x2-1)+1]
對(duì)任意不小于2的正整數(shù)n都成立,求實(shí)數(shù)x的取值范圍.

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已知定義域在R上的單調(diào)函數(shù),存在實(shí)數(shù)x0,使得對(duì)于任意的實(shí)數(shù)x1,x2總有f(x0x1+x0x2)=f(x0)+f(x1)+f(x2)恒成立.
(1)求x0的值;
(2)若f(1)=1,且對(duì)于任意的正整數(shù)n,有an=數(shù)學(xué)公式,bn=f(數(shù)學(xué)公式)+1
(Ⅰ)若Sn=a1a2+a2a3+…+anan+1,求Sn;
(Ⅱ)若Tn=b1b2+b2b3+…+bnbn+1,求Tn

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已知定義域在R上的單調(diào)函數(shù)y=f(x),存在實(shí)數(shù)x0,使得對(duì)于任意的實(shí)數(shù)x1,x2,總有f(x0x1+x0x2)=f(x0)+f(x1)+f(x2)恒成立.
(1)求x0的值;
(2)若f(x0)=1,且對(duì)任意正整數(shù)n,有an=
1
f(n)
,bn=f(
1
2n
)+1,記Tn=b1b2+b2b3+…+bnbn+1,求an與Tn;
(3)在(2)的條件下,若不等式an+1+an+2+…+a2n
4
35
[log
1
2
(x+1)-log
1
2
(9x2-1)+1]
對(duì)任意不小于2的正整數(shù)n都成立,求實(shí)數(shù)x的取值范圍.

查看答案和解析>>

已知定義域在R上的單調(diào)函數(shù),存在實(shí)數(shù)x0,使得對(duì)于任意的實(shí)數(shù)x1,x2總有f(x0x1+x0x2)=f(x0)+f(x1)+f(x2)恒成立.
(1)求x0的值;
(2)若f(1)=1,且對(duì)于任意的正整數(shù)n,有an=
1
f(n)
,bn=f(
1
2n
)+1
(Ⅰ)若Sn=a1a2+a2a3+…+anan+1,求Sn;
(Ⅱ)若Tn=b1b2+b2b3+…+bnbn+1,求Tn

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已知定義域在R上的單調(diào)函數(shù)y=f(x),存在實(shí)數(shù)x,使得對(duì)于任意的實(shí)數(shù)x1,x2,總有f(xx1+xx2)=f(x)+f(x1)+f(x2)恒成立.
(1)求x的值;
(2)若f(x)=1,且對(duì)任意正整數(shù)n,有an=,bn=f()+1,記Tn=b1b2+b2b3+…+bnbn+1,求an與Tn;
(3)在(2)的條件下,若不等式對(duì)任意不小于2的正整數(shù)n都成立,求實(shí)數(shù)x的取值范圍.

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