【題目】寬9 m的成型玻璃以2 m/s的速度連續(xù)不斷地向前行進,在切割工序處,金剛割刀的速度為10 m/s,為了使割下的玻璃板都成規(guī)定尺寸的矩形,則:

1金剛割刀的軌道應(yīng)如何控制?

2切割一次的時間多長?

3所生產(chǎn)的玻璃板的規(guī)格是怎樣的?

【答案】1割刀速度方向與玻璃板速度方向成arccos角度 2092 s 3長9 m、寬184 m

【解析】1由題目條件知,割刀運動的速度是實際的速度,所以為合速度其分速度的效果恰好相對玻璃垂直切割

設(shè)割刀的速度v1的方向與玻璃板速度v2的方向之間的夾角為θ,如圖所示。要保證割下均是矩形的玻璃板,則由v1是合速度得v2=v1cos θ

所以cos θ=,即θ=arccos

所以,要割下矩形板,割刀速度方向與玻璃板速度方向所成角度為θ=arccos

2切割一次的時間t= s≈092 s

3切割出的矩形玻璃板的規(guī)格為:長度d=9 m

寬度:l=v2t=2×092 m=184 m

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