計算化簡:
6y
x2-y2
-
2
y-x
+
3
x+y
=
5
x-y
5
x-y
分析:先把各分式的分子或分母因式分解得到原式=
6y
(x+y)(x-y)
+
2
x-y
+
3
x+y
,然后通分得到原式=
6y
(x+y)(x-y)
+
2(x+y)
(x+y)(x-y)
+
3(x-y)
(x+y)(x-y)
,再把分子進行加減運算,得到原式=
6y
(x+y)(x-y)
+
2(x+y)
(x+y)(x-y)
+
3(x-y)
(x+y)(x-y)
,然后約分即可.
解答:解:原式=
6y
(x+y)(x-y)
+
2
x-y
+
3
x+y

=
6y
(x+y)(x-y)
+
2(x+y)
(x+y)(x-y)
+
3(x-y)
(x+y)(x-y)

=
6y+2x+2y+3x-3y
(x+y)(x-y)

=
6y
(x+y)(x-y)
+
2(x+y)
(x+y)(x-y)
+
3(x-y)
(x+y)(x-y)

=
5(x+y)
(x+y)(x-y)

=
5
x-y

故答案為
5
x-y
點評:本題考查了分式的加減法:先把各分式的分子或分母因式分解,確定各分式的最簡公分母,然后把各分式進行通分,再把分子進行加減運算,最后化為最簡分式或整式.
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計算化簡:
6y
x2-y2
-
2
y-x
+
3
x+y
=______.

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